I need to extract the name of the parent directory of a certain path. This is what it looks like:
I am modifying the content of the "file" with something that uses the
directory_i_need name in it (not the path). I have created a function that will give me a list of all the files, and then...
for path in file_list: #directory_name = os.path.dirname(path) # this is not what I need, that's why it is commented directories, files = path.split('\\') line_replace_add_directory = line_replace + directories # this is what I want to add in the text, with the directory name at the end # of the line.
How can I do that?
import os ## first file in current dir (with full path) file = os.path.join(os.getcwd(), os.listdir(os.getcwd())) file os.path.dirname(file) ## directory of file os.path.dirname(os.path.dirname(file)) ## directory of directory of file ...
And you can continue doing this as many times as necessary...
Edit: from os.path, you can use either os.path.split or os.path.basename:
dir = os.path.dirname(os.path.dirname(file)) ## dir of dir of file ## once you're at the directory level you want, with the desired directory as the final path node: dirname1 = os.path.basename(dir) dirname2 = os.path.split(dir) ## if you look at the documentation, this is exactly what os.path.basename does.
In Python 3.4 you can use the pathlib module:
>>> from pathlib import Path >>> p = Path('C:\Program Files\Internet Explorer\iexplore.exe') >>> p.name 'iexplore.exe' >>> p.suffix '.exe' >>> p.root '\\' >>> p.parts ('C:\\', 'Program Files', 'Internet Explorer', 'iexplore.exe') >>> p.relative_to('C:\Program Files') WindowsPath('Internet Explorer/iexplore.exe') >>> p.exists() True