Convert a string to integer with decimal in Python

Question

I have a string in the format: 'nn.nnnnn' in Python, and I'd like to convert it to an integer.

Direct conversion fails:

``````>>> s = '23.45678'
>>> i = int(s)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
ValueError: invalid literal for int() with base 10: '23.45678'
``````

I can convert it to a decimal by using:

``````>>> from decimal import *
>>> d = Decimal(s)
>>> print d
23.45678
``````

I could also split on '.', then subtract the decimal from zero, then add that to the whole number ... yuck.

But I'd prefer to have it as an int, without unnecessary type conversions or maneuvering.

1
51
7/7/2009 8:35:48 PM

``````>>> s = '23.45678'
>>> int(float(s))
23
``````

Or...

``````>>> int(Decimal(s))
23
``````

Or...

``````>>> int(s.split('.')[0])
23
``````

I doubt it's going to get much simpler than that, I'm afraid. Just accept it and move on.

103
7/7/2009 8:36:52 PM

What sort of rounding behavior do you want? Do you 2.67 to turn into 3, or 2. If you want to use rounding, try this:

``````s = '234.67'
i = int(round(float(s)))
``````

Otherwise, just do:

``````s = '234.67'
i = int(float(s))
``````