What does the python interface to opencv2.fillPoly want as input?


I'm trying to draw a polygon using the python interface to opencv, cv2. I've created an empty image, just a 640x480 numpy array. I have a list of polygons (four point quadrilaterals) that I want to draw on the image, however, I can't seem to get the formate right to instruct cv2 where the quadrilaterals should be, and I keep getting this error:

OpenCV Error: Assertion failed (points.checkVector(2, CV_32S) >= 0) in fillConvexPoly, file .../OpenCV-2.4.0/modules/core/src/drawing.cpp, line 2017

My code consists of essentially the following:

binary_image = np.zeros(image.shape,dtype='int8')
for rect in expected:
    cv2.fillConvexPoly(binary_image, np.array(rect['boundary']), 255)
fig = pyplot.figure(figsize=(16, 14))
ax = fig.add_subplot(111)

where my list of rects in expected has the 'boundary' containing the value of a list of (x,y) points. The code prints:

[[ 91 233]
 [419 227]
 [410 324]
 [ 94 349]]

I figured that this is the list of points for a polygon, but apparently that list has an invalid points.checkvector, whatever that is. A google search for that error turned up nothing useful.

7/1/2012 12:33:42 AM

Accepted Answer

The AssertionError is telling you that OpenCV wants a signed, 32-bit integer. The array of polygon points should have that particular data type (e.g. points = numpy.array(A,dtype='int32') ). You could also just cast it for the function call (i.e. my_array.astype('int32') ) or as a friend put it once...

" Changing

   cv2.fillConvexPoly(binary_image, np.array(rect['boundary']), 255) to

   cv2.fillConvexPoly(binary_image, np.array(rect['boundary'], 'int32'), 255) "

5/16/2018 5:27:47 PM

import numpy as np
import cv2
import matplotlib.pyplot as plt

a3 = np.array( [[[10,10],[100,10],[100,100],[10,100]]], dtype=np.int32 )
im = np.zeros([240,320],dtype=np.uint8)
cv2.fillPoly( im, a3, 255 )


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