Remove all occurrences of a value from a list?


Question

In Python remove() will remove the first occurrence of value in a list.

How to remove all occurrences of a value from a list?

This is what I have in mind:

>>> remove_values_from_list([1, 2, 3, 4, 2, 2, 3], 2)
[1, 3, 4, 3]
1
324
6/26/2019 1:53:21 PM

Accepted Answer

Functional approach:

2.x

>>> x = [1,2,3,2,2,2,3,4]
>>> filter(lambda a: a != 2, x)
[1, 3, 3, 4]

3.x

>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter((2).__ne__, x))
[1, 3, 3, 4]

or

>>> x = [1,2,3,2,2,2,3,4]
>>> list(filter(lambda a: a != 2, x))
[1, 3, 3, 4]
440
1/31/2017 2:13:22 PM

You can use a list comprehension:

def remove_values_from_list(the_list, val):
   return [value for value in the_list if value != val]

x = [1, 2, 3, 4, 2, 2, 3]
x = remove_values_from_list(x, 2)
print x
# [1, 3, 4, 3]

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