**How to create a list of consecutive numbers in Common Lisp?**

In other words, what is the equivalent of Python's `range`

function in Common Lisp?

In Python `range(2, 10, 2)`

returns `[2, 4, 6, 8]`

, with first and last arguments being optional. I couldn't find the idiomatic way to create a sequence of numbers, though Emacs Lisp has `number-sequence`

.

Range could be emulated using loop macro, but i want to know the accepted way to generate a sequence of numbers with start and end points and step.

Related: Analog of Python's range in Scheme

There is no built-in way of generating a sequence of numbers, the canonical way of doing so is to do one of:

- Use
`loop`

- Write a utility function that uses
`loop`

An example implementation would be (this only accepts counting "from low" to "high"):

```
(defun range (max &key (min 0) (step 1))
(loop for n from min below max by step
collect n))
```

This allows you to specify an (optional) minimum value and an (optional) step value.

To generate odd numbers: `(range 10 :min 1 :step 2)`

alexandria implements scheme's iota:

```
(ql:quickload :alexandria)
(alexandria:iota 4 :start 2 :step 2)
;; (2 4 6 8)
```

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