Create Django model or update if exists


Question

I want to create a model object, like Person, if person's id doesn't not exist, or I will get that person object.

The code to create a new person as following:

class Person(models.Model):
    identifier = models.CharField(max_length = 10)
    name = models.CharField(max_length = 20)
    objects = PersonManager()

class PersonManager(models.Manager):
    def create_person(self, identifier):
        person = self.create(identifier = identifier)
        return person

But I don't know where to check and get the existing person object.

1
93
6/2/2015 9:29:13 PM

Accepted Answer

If you're looking for "update if exists else create" use case, please refer to @Zags excellent answer


Django already has a get_or_create, https://docs.djangoproject.com/en/dev/ref/models/querysets/#get-or-create

For you it could be :

id = 'some identifier'
person, created = Person.objects.get_or_create(identifier=id)

if created:
   # means you have created a new person
else:
   # person just refers to the existing one
145
4/11/2018 7:36:39 PM

It's unclear whether your question is asking for the get_or_create method (available from at least Django 1.3) or the update_or_create method (new in Django 1.7). It depends on how you want to update the user object.

Sample use is as follows:

# In both cases, the call will get a person object with matching
# identifier or create one if none exists; if a person is created,
# it will be created with name equal to the value in `name`.

# In this case, if the Person already exists, its existing name is preserved
person, created = Person.objects.get_or_create(
        identifier=identifier, defaults={"name": name}
)

# In this case, if the Person already exists, its name is updated
person, created = Person.objects.update_or_create(
        identifier=identifier, defaults={"name": name}
)

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