I have ABC123EFFF.

I want to have 001010101111000001001000111110111111111111 (i.e. binary repr. with, say, 42 digits and leading zeroes).

How?

For solving the left-side trailing zero problem:

```
my_hexdata = "1a"
scale = 16 ## equals to hexadecimal
num_of_bits = 8
bin(int(my_hexdata, scale))[2:].zfill(num_of_bits)
```

It will give 00011010 instead of the trimmed version.

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