I have ABC123EFFF.
I want to have 001010101111000001001000111110111111111111 (i.e. binary repr. with, say, 42 digits and leading zeroes).
For solving the left-side trailing zero problem:
my_hexdata = "1a" scale = 16 ## equals to hexadecimal num_of_bits = 8 bin(int(my_hexdata, scale))[2:].zfill(num_of_bits)
It will give 00011010 instead of the trimmed version.