# Python first and last element from array

### Question

I am trying to dynamically get the first and last element from an array.

So, let us suppose the array has 6 elements.

``````test = [1,23,4,6,7,8]
``````

If I am trying to get the `first and last = 1,8`, `23,7` and `4,6`. Is there a way to get elements in this order? I looked at a couple of questions Link Link2. I took help of these links and I came up with this prototype..

``````#!/usr/bin/env python

import numpy

test = [1,23,4,6,7,8]
test1 = numpy.array([1,23,4,6,7,8])
len_test = len(test)
first_list = [0,1,2]
len_first = len(first_list)
second_list = [-1,-2,-3]
len_second = len(second_list)

for a in range(len_first):
print numpy.array(test)[[first_list[a] , second_list[a]]]
print test1[[first_list[a], second_list[a]]]
``````

But this prototype won't scale for if you have more than 6 elements. So, I was wondering if there is way to dynamically get the pair of elements.

Thanks!

1
34
5/23/2017 12:26:20 PM

``````In : arr = numpy.array([1,23,4,6,7,8])

In : [(arr[i], arr[-i-1]) for i in range(len(arr) // 2)]
Out: [(1, 8), (23, 7), (4, 6)]
``````

Depending on the size of `arr`, writing the entire thing in NumPy may be more performant:

``````In : arr = numpy.array([1,23,4,6,7,8]*100)

In : %timeit [(arr[i], arr[-i-1]) for i in range(len(arr) // 2)]
10000 loops, best of 3: 167 us per loop

In : %timeit numpy.vstack((arr, arr[::-1]))[:,:len(arr)//2]
100000 loops, best of 3: 16.4 us per loop
``````
23
1/30/2013 5:26:18 PM

I ended here, because I googled for "python first and last element of array", and found everything else but this. So here's the answer to the title question:

``````a = [1,2,3]
a # first element (returns 1)
a[-1] # last element (returns 3)
``````