Easy pretty printing of floats in python?


I have a list of floats. If I simply print it, it shows up like this:

[9.0, 0.052999999999999999, 0.032575399999999997, 0.010892799999999999, 0.055702500000000002, 0.079330300000000006]

I could use print "%.2f", which would require a for loop to traverse the list, but then it wouldn't work for more complex data structures. I'd like something like (I'm completely making this up)

>>> import print_options
>>> print_options.set_float_precision(2)
>>> print [9.0, 0.052999999999999999, 0.032575399999999997, 0.010892799999999999, 0.055702500000000002, 0.079330300000000006]
[9.0, 0.05, 0.03, 0.01, 0.06, 0.08]
5/10/2012 5:15:10 PM

Accepted Answer

It's an old question but I'd add something potentially useful:

I know you wrote your example in raw Python lists, but if you decide to use numpy arrays instead (which would be perfectly legit in your example, because you seem to be dealing with arrays of numbers), there is (almost exactly) this command you said you made up:

import numpy as np

Or even better in your case if you still want to see all decimals of really precise numbers, but get rid of trailing zeros for example, use the formatting string %g:

np.set_printoptions(formatter={"float_kind": lambda x: "%g" % x})

For just printing once and not changing global behavior, use np.array2string with the same arguments as above.

5/3/2018 11:37:16 AM

As noone has added it, it should be noted that going forward from Python 2.6+ the recommended way to do string formating is with format, to get ready for Python 3+.

print ["{0:0.2f}".format(i) for i in a]

The new string formating syntax is not hard to use, and yet is quite powerfull.

I though that may be pprint could have something, but I haven't found anything.

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