Find Monday's date with Python


How do I find the previous Monday's date, based off of the current date using Python? I thought maybe I could use: datetime.weekday() to do it, but I am getting stuck.

I basically want to find today's date and Mondays date to construct a date range query in django using: created__range=(start_date, end_date).

10/25/2009 9:28:05 PM

Accepted Answer

>>> import datetime
>>> today =
>>> today + datetime.timedelta(days=-today.weekday(), weeks=1), 10, 26)

Some words of explanation:

Take todays date. Subtract the number of days which already passed this week (this gets you 'last' monday). Add one week.

Edit: The above is for 'next monday', but since you were looking for 'last monday' you could use

today - datetime.timedelta(days=today.weekday())
10/26/2009 6:47:01 AM

ChristopheD's post is close to what you want. I don't have enough rep to make a comment :(

Instead of (which actually gives you the next upcoming monday):

>>> today + datetime.timedelta(days=-today.weekday(), weeks=1), 10, 26)

I would say:

>>> last_monday = today - datetime.timedelta(days=today.weekday())

If you want the previous week, add the 'weeks=1' parameter.

This makes the code more readable since you are subtracting a timedelta. This clears up any confusion caused by adding a timedelta that has negative and positive offsets.

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