How to define two fields "unique" as couple


Question

Is there a way to define a couple of fields as unique in Django?

I have a table of volumes (of journals) and I don't want more then one volume number for the same journal.

class Volume(models.Model):
    id = models.AutoField(primary_key=True)
    journal_id = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name = "Journal")
    volume_number = models.CharField('Volume Number', max_length=100)
    comments = models.TextField('Comments', max_length=4000, blank=True)

I tried to put unique = True as attribute in the fields journal_id and volume_number but it doesn't work.

1
327
12/19/2015 7:29:21 AM

Accepted Answer

There is a simple solution for you called unique_together which does exactly what you want.

For example:

class MyModel(models.Model):
  field1 = models.CharField(max_length=50)
  field2 = models.CharField(max_length=50)

  class Meta:
    unique_together = ('field1', 'field2',)

And in your case:

class Volume(models.Model):
  id = models.AutoField(primary_key=True)
  journal_id = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name = "Journal")
  volume_number = models.CharField('Volume Number', max_length=100)
  comments = models.TextField('Comments', max_length=4000, blank=True)

  class Meta:
    unique_together = ('journal_id', 'volume_number',)
547
6/16/2014 8:50:11 PM

Django 2.2+

Use UniqueConstraint with the constraints option instead. It provides more functionality than unique_together, which may be deprecated in the future.

For example:

class Volume(models.Model):
    id = models.AutoField(primary_key=True)
    journal_id = models.ForeignKey(Journals, db_column='jid', null=True, verbose_name="Journal")
    volume_number = models.CharField('Volume Number', max_length=100)
    comments = models.TextField('Comments', max_length=4000, blank=True)

    class Meta:
        constraints = [
            models.UniqueConstraint(fields=['journal_id', 'volume_number'], name='name of constraint')
        ]

Licensed under: CC-BY-SA with attribution
Not affiliated with: Stack Overflow
Icon