Django, template context processors


Question

I have a weird problem, I want to add a global query using context processors. This is how I did it by following:

made a processor.py in my app as such:

from myproject.myapp.models import Foo

def foos(request):
    return {'foos': Foo.objects.all()}

and at the end of my setting.py I have added this:

TEMPLATE_CONTEXT_PROCESSORS = ('myapp.processor.foos',)

Lastly I pass my view as this:

def index_view(request):

    return render_to_response('index.html', {}, context_instance=RequestContext(request))

and at my index.html template:

<select id="select_foo">
{% for foo in foos %}
    <option value="/{{ foo.slug }}">{{ foo.name }}</option>
{% endfor %}
</select>

And lastly my url:

(r'^$', 'myapp.views.index_view'),

My foos display without any problem, however my media_url and other contexts are gone. What can be the issue

1
60
2/11/2010 6:34:03 PM

Accepted Answer

When you specify this:

TEMPLATE_CONTEXT_PROCESSORS = ('myapp.processor.foos',)

In your settings file, you are overriding the Django's default context processors. In order to extend the list, you need to include the default ones in your settings:

TEMPLATE_CONTEXT_PROCESSORS = (
    "django.core.context_processors.auth",
    "django.core.context_processors.debug",
    "django.core.context_processors.i18n",
    "django.core.context_processors.media",
    "myapp.processor.foos",
)

Note, the settings above are the defaults (plus your processor) for django 1.1.

54
1/20/2016 2:42:48 AM

You need to add the default values of TEMPLATE_CONTEXT_PROCESSORS. However, instead of hard-coding those values, which will be tied to a specific version of Django, you can append your context processor to the default values by the following:

from django.conf import global_settings
TEMPLATE_CONTEXT_PROCESSORS = global_settings.TEMPLATE_CONTEXT_PROCESSORS + (
    "myapp.processor.foos",
)

Make sure to include the trailing comma in the tuple, so that Python recognizes it as a tuple.


Licensed under: CC-BY-SA with attribution
Not affiliated with: Stack Overflow
Icon