I have a sentence. I want to find all occurrences of a word that start with a specific character in that sentence. I am very new to programming and Python, but from the little I know, this sounds like a Regex question.
What is the pattern match code that will let me find all words that match my pattern?
Many thanks in advance,
import re print re.findall(r'\bv\w+', thesentence)
will print every word in the sentence that starts with
'v', for example.
split method of strings, as another answer suggests, would not identify words, but space-separated chunks that may include punctuation. This
re-based solution does identify words (letters and digits, net of punctuation).
I second the Dive Into Python recommendation. But it's basically:
m = re.findall(r'\bf.*?\b', 'a fast and friendly dog') print(m)
\b means word boundary, and .*? ensures we store the whole word, but back off to avoid going too far (technically, ? is called a lazy operator).