Python list directory, subdirectory, and files


I'm trying to make a script to list all directory, subdirectory, and files in a given directory.
I tried this:

import sys,os

root = "/home/patate/directory/"
path = os.path.join(root, "targetdirectory")

for r,d,f in os.walk(path):
    for file in f:
        print os.path.join(root,file)

Unfortunatly it doesn't work properly.
I get all the files, but not their complete paths.

For example if the dir struct would be:


It would print:


What I need is the first result. Any help would be greatly appreciated! Thanks.

5/26/2010 4:16:25 AM

Accepted Answer

Use os.path.join to concatenate the directory and file name:

for path, subdirs, files in os.walk(root):
    for name in files:
        print os.path.join(path, name)

Note the usage of path and not root in the concatenation, since using root would be incorrect.

In Python 3.4, the pathlib module was added for easier path manipulations. So the equivalent to os.path.join would be:

pathlib.PurePath(path, name)

The advantage of pathlib is that you can use a variety of useful methods on paths. If you use the concrete Path variant you can also do actual OS calls through them, like chanding into a directory, deleting the path, opening the file it points to and much more.

11/24/2013 6:24:00 PM

Just in case... Getting all files in the directory and subdirectories matching some pattern (*.py for example):

import os
from fnmatch import fnmatch

root = '/some/directory'
pattern = "*.py"

for path, subdirs, files in os.walk(root):
    for name in files:
        if fnmatch(name, pattern):
            print os.path.join(path, name)

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