Launch a shell command with in a python script, wait for the termination and return to the script


Question

I've a python script that has to launch a shell command for every file in a dir:

import os

files = os.listdir(".")
for f in files:
    os.execlp("myscript", "myscript", f)

This works fine for the first file, but after the "myscript" command has ended, the execution stops and does not come back to the python script.

How can I do? Do I have to fork() before calling os.execlp()?

1
53
11/28/2008 11:35:06 AM

Accepted Answer

subprocess: The subprocess module allows you to spawn new processes, connect to their input/output/error pipes, and obtain their return codes.

http://docs.python.org/library/subprocess.html

Usage:

import subprocess
process = subprocess.Popen(command, shell=True, stdout=subprocess.PIPE)
process.wait()
print process.returncode
88
10/28/2015 9:19:05 AM

You can use subprocess.Popen. There's a few ways to do it:

import subprocess
cmd = ['/run/myscript', '--arg', 'value']
p = subprocess.Popen(cmd, stdout=subprocess.PIPE)
for line in p.stdout:
    print line
p.wait()
print p.returncode

Or, if you don't care what the external program actually does:

cmd = ['/run/myscript', '--arg', 'value']
subprocess.Popen(cmd).wait()

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