How to pass variable arguments from bash script to python script


I've been trying to solve this issue for sometime now with no luck. The crust of the situation is that I'm using a bash script to send parameters to a a python script:

Example: calls call looks like: $var1 $var2 ... $varn

The python script then prints all the arguments using the sys.argv array. The python script works correctly from the command line, but when called from with the bash script (i.e, I get no output from

Also, I started with the "#!/bin/bash -x" option and watched the output as well.

TO summarize:

  • Two scripts, and
  • calls, passing variables of as arguments to
  • prints the arguments it sees using sys.argv
  • works when run from its own terminal, doesn't work when called from

Any help would be awesome!!!!


Edit: Hi all, thanks for the replies, the complete code is pretty long...but... the contents of the two scripts could be summed ____

declare -a list1;  
declare -a list2;  

list1=("foo" "bar" "please");  
list2=("foo" "bar" "please" "help");  

declare -a joined;  

joined=( $( "${list1[@]}" "${list2[@]}" ) ); ____

import sys  

for arg in sys.argv:  
    print arg  

As I assume all the indents in the python are correct (not sure how StackOverflow does this yet :) ). These two represent the core of the issue i'm having. As stated, prints arguments correctly, when it it not called from

PS: I did mean to say "crust"

10/18/2010 4:26:00 AM

Accepted Answer

Edit, since code has been posted

Your code is doing the correct thing - except that the output from your script is being captured into the array joined. Since it looks like you're not printing out the contents of joined, you never see any output.

Here's a demonstration:



declare -a list1
declare -a list2

list1=("Hello" "there" "honey")
list2=("More" "strings" "here")

declare -a joined

joined=($(./ ${list1[@]} ${list2[@]}))
echo ${joined[@]}



import sys

for i in sys.argv:
    print "hi"

This will print out a bunch of 'hi' strings if you run the bash script.

10/18/2010 4:36:40 AM


I figured it out, I had some weired combo of characters, the line was not properly escaped. I changed it from

var=( $( some commands) )


var=( some commands ) // using backticks (still learning the SO editor...)

Bash escaping is some ride lol! To those who answered, thanks for all your help

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