How can you dynamically create variables via a while loop?


I want to create variables dynamically via a while loop in Python. Does anyone have any creative means of doing this?

7/5/2018 11:08:23 AM

Accepted Answer

Unless there is an overwhelming need to create a mess of variable names, I would just use a dictionary, where you can dynamically create the key names and associate a value to each.

a = {}
k = 0
while k < 10:
    <dynamically create key> 
    key = ...
    <calculate value> 
    value = ...
    a[key] = value 
    k += 1

There are also some interesting data structures in the new 'collections' module that might be applicable:

2/18/2011 2:37:58 AM

playing with globals() makes it possible:

import random

alphabet = tuple('abcdefghijklmnopqrstuvwxyz')

print '\n'.join(repr(u) for u in globals() if not u.startswith('__'))

for i in xrange(8):
    globals()[''.join(random.sample(alphabet,random.randint(3,26)))] = random.choice(alphabet)


print '\n'.join(repr((u,globals()[u])) for u in globals() if not u.startswith('__'))

one result:


('hadmgoixzkcptsbwjfyrelvnqu', 'h')
('nzklv', 'o')
('alphabet', ('a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'x', 'y', 'z'))
('random', <module 'random' from 'G:\Python27\lib\random.pyc'>)
('ckpnwqguzyslmjveotxfbadh', 'f')
('i', 7)
('xwbujzkicyd', 'j')
('isjckyngxvaofdbeqwutl', 'n')
('wmt', 'g')
('aesyhvmw', 'q')
('azfjndwhkqgmtyeb', 'o')

I used random because you don't explain which names of "variables" to give, and which values to create. Because i don't think it's possible to create a name without making it binded to an object.

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