Dynamic choices field in Django Models


Question

My models.py:

SHOP1_CHOICES = (
    ('Food Court', 'Food Court'),
    ('KFC', 'KFC'),

)

SHOP2_CHOICES = (
    ('Sports Arena', 'Sports Arena'),
    ('Disco D', 'Disco D'),

)

SHOP3_CHOICES = (
    ('Bowling Arena', 'Bowling Arena'),
    ('Cinemax', 'Cinemax'),

)

class Feed(models.Model):
  gender = models.CharField(max_length=5, choices=GENDER_CHOICES, default='girl')
  name =models.CharField(max_length=25)
  shop=models.CharField(max_length=20)
  location=models.CharField(max_length=25, choices=SHOP1_CHOICES)

Here if Feed.shop == 'shop1' I want to load SHOP1_CHOICES on Feed.location. Currently irrespective of what shop, it just displays the SHOP1_CHOICES (no surprise).How can I implement it? I am stuck, please help.

1
14
3/26/2014 8:46:17 PM

This is my approach:

I use lazy for lazy load:

from django.utils.functional import lazy

Here, a helper to chose options:

def help_SHOP_CHOICES():
    SHOP1_CHOICES = [
        ('Food Court', 'Food Court'),
        ('KFC', 'KFC'),
      ]
    SHOP3_CHOICES = [
        ('Bowling Arena', 'Bowling Arena'),
        ('Cinemax', 'Cinemax'),
      ]
    return random.choice( SHOP1_CHOICES + SHOP3_CHOICES )   # choose one

Finally the model with dynamic choices:

class Feed(models.Model):
  ...
  location=models.CharField(max_length=25, choices=SHOP1_CHOICES)

  def __init__(self, *args, **kwargs):
     super(Feed, self).__init__(*args, **kwargs)
     self._meta.get_field('location').choices = \
                        lazy(help_SHOP_CHOICES,list)()
16
6/15/2018 9:35:05 AM

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