How to import a module given the full path?


Question

How can I load a Python module given its full path? Note that the file can be anywhere in the filesystem, as it is a configuration option.

1
966
2/16/2014 3:36:02 PM

Accepted Answer

For Python 3.5+ use:

import importlib.util
spec = importlib.util.spec_from_file_location("module.name", "/path/to/file.py")
foo = importlib.util.module_from_spec(spec)
spec.loader.exec_module(foo)
foo.MyClass()

For Python 3.3 and 3.4 use:

from importlib.machinery import SourceFileLoader

foo = SourceFileLoader("module.name", "/path/to/file.py").load_module()
foo.MyClass()

(Although this has been deprecated in Python 3.4.)

For Python 2 use:

import imp

foo = imp.load_source('module.name', '/path/to/file.py')
foo.MyClass()

There are equivalent convenience functions for compiled Python files and DLLs.

See also http://bugs.python.org/issue21436.

1116
5/9/2019 12:06:42 PM

The advantage of adding a path to sys.path (over using imp) is that it simplifies things when importing more than one module from a single package. For example:

import sys
# the mock-0.3.1 dir contains testcase.py, testutils.py & mock.py
sys.path.append('/foo/bar/mock-0.3.1')

from testcase import TestCase
from testutils import RunTests
from mock import Mock, sentinel, patch

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