Let me start off by saying that I am COMPLETELY new to programming. I have just recently picked up Python and it has consistently kicked me in the head with one recurring error -- "expected an indented block" Now, I know there are several other threads addressing this problem and I have looked over a good number of them, however, even checking my indentation has not given me better results. I have replaced all of my indents with 4 spaces and even rewritten the code several times. I'll post this counter assignment I got as an example.
option == 1 while option != 0: print "MENU" option = input() print "please make a selection" print "1. count" print "0. quit" if option == 1: while option != 0: print "1. count up" print "2. count down" print "0. go back" if option == 1: print "please enter a number" for x in range(1, x, 1): print x elif option == 2: print "please enter a number" for x in range(x, 1, 1): elif option == 0: break else: print "invalid command" elif option == 0: break
elif option == 2:, you indented one time too many. In a decent text editor, you should be able to highlight these lines and press Shift+Tab to fix the issue.
Additionally, there is no statement after
for x in range(x, 1, 1):. Insert an indented
pass to do nothing in the
Also, in the first line, you wrote
option == 1.
== tests for equality, but you meant
= ( a single equals sign), which assigns the right value to the left name, i.e.
option = 1