Aim to Achieve:
I want all objects where name attribute contains any word from the list.
list = ['word1','word2','word3'] ob_list = data.objects.filter( // What to write here ? ) // or any other way to get the objects where any word in list is contained, in // the na-me attribute of data.
if name="this is word2": Then object with such a name should be returned since word2 is in the list.
You could use
Q objects to constuct a query like this:
from django.db.models import Q ob_list = data.objects.filter(reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))
reduce(lambda x, y: x | y, [Q(name__contains=word) for word in list]))
is a fancy way to write
Q(name__contains=list) | Q(name__contains=list) | ... | Q(name__contains=list[-1])
You could also use an explicit for loop to construct the
ob_list = data.objects.filter(name__in=my_list)
And BTW, avoid using the variable name "list" (Or any other python standard keyword), lest you get into some weird bugs later.
Update: (I guess your question was updated too, because when I wrote the answer, I didn't see the part where you wrote you need a contains match and not an exact match)
You can do that using the regex search too, avoiding many Q expressions (which end up using that many where "and" clauses in the SQL, possibly dampening the performance), as follows: