I'm trying to find a short way to see if any of the following items is in a list, but my first attempt does not work. Besides writing a function to accomplish this, is the any short way to check if one of multiple items is in a list.
>>> a = [2,3,4] >>> print (1 or 2) in a False >>> print (2 or 1) in a True
>>> L1 = [2,3,4] >>> L2 = [1,2] >>> [i for i in L1 if i in L2]  >>> S1 = set(L1) >>> S2 = set(L2) >>> S1.intersection(S2) set()
Both empty lists and empty sets are False, so you can use the value directly as a truth value.
Ah, Tobias you beat me to it. I was thinking of this slight variation on your solution:
>>> a = [1,2,3,4] >>> b = [2,7] >>> print(any(x in a for x in b)) True